• 个人简介

    #include <bits/stdc++.h>

    using namespace std;

    signed main() {

    int n;
    cin >> n;
    int a[100001];
    int sum=0;
    for (int i = 1;i <= n;i++)
    {
    	cin >> a[i];
    }
    for (int i = 1;i <= n;i++)
    {
    	for (int j = i+1;j <= n;j++)
    	{
    		sum+=a[i]*a[j];
    	}
    }
    cout << sum;
    return 0;
    

    }

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    This person is lazy and didn't write any solutions.
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