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个人简介
#include <bits/stdc++.h>
using namespace std;
signed main() {
int n; cin >> n; int a[100001]; int sum=0; for (int i = 1;i <= n;i++) { cin >> a[i]; } for (int i = 1;i <= n;i++) { for (int j = i+1;j <= n;j++) { sum+=a[i]*a[j]; } } cout << sum; return 0;}
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最近活动
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最近编写的题解
This person is lazy and didn't write any solutions.